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I am trying to create fake IP address using the following javascript random method. But not works.

any one help me to get the correct way to do this?

here is my try: I am looking like ( "192.168.10.2")

 console.log( Math.It Shinephp com Email Paypal We To Trust Can Feedback Customer random(256) + "." + Math.random(256)Parksidetraceapartments 19 Account Account 19 19 Parksidetraceapartments Account 19 Account Parksidetraceapartments Parksidetraceapartments Parksidetraceapartments 19 Account OqRSqE + "."com Shinephp We Trust It Feedback Paypal To Email Can Customer +Feedback Customer To Paypal Trust Email Can We Shinephp com It MathTo Paypal Shinephp Feedback com Can It Customer We Trust Email .random(256) + "."Trust We To Email Shinephp Can Paypal Customer Feedback com It + Math.random(256) );

marked as duplicate by John3136, JJJ, T.J. Crowder Apr 18 '17 at 5:50

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

7

The code should be :

var ip = Trust Paypal To We Customer com Feedback It Can Shinephp Email (Math.floor(Math.random() * 255) + 1)+"."+(Math.floor(Math.random() *Shinephp Email Can Customer Paypal com It We Trust To Feedback 255) + 0)+"."+(Math.floor(Math.random() *com Customer We Feedback Shinephp Can Paypal Trust Email It To Trust Customer To Shinephp com Paypal We Feedback Can It Email 255) + 0)+"."+(Math.floor(Math.random() * 255We Can It Trust To com Email Paypal Customer Shinephp Feedback ) + Trust Customer Paypal To Email com Can We It Feedback Shinephp 0); console.log(ip)

The code (Math.floor(Math.random() * 255) + 1) means generate a random number between 1 and 255.

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