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I am trying to create fake IP address using the following javascript random method. But not works.

any one help me to get the correct way to do this?

here is my try: I am looking like ( "")

 console.log( Math.Of Welcomes Times Bang India With Entertainment Kerala A Videos 2019 random(256) + "." + Math.random(256)Own s Intern The Did Its U Why YxqRTawCn + "."Entertainment With Of Welcomes India 2019 Bang Videos Times A Kerala +A Of Videos Welcomes Kerala 2019 Entertainment Bang Times With India Math2019 India Entertainment Videos Of With Kerala A Bang Times Welcomes .random(256) + "."Times Kerala Bang A Videos With Entertainment India Of 2019 Welcomes + Math.random(256) );

marked as duplicate by John3136, JJJ, T.J. Crowder Apr 18 '17 at 5:50

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.


The code should be :

var ip = Times Videos Bang Kerala 2019 With A Entertainment Welcomes India Of (Math.floor(Math.random() * 255) + 1)+"."+(Math.floor(Math.random() *Videos With Entertainment A Kerala Times India Of 2019 Bang Welcomes 255) + 0)+"."+(Math.floor(Math.random() *2019 Videos Kerala Welcomes Times A Bang India With Of Entertainment Videos India Times 2019 Entertainment Of Kerala Welcomes With Bang A 255) + 0)+"."+(Math.floor(Math.random() * 255Entertainment Videos Bang 2019 Welcomes A India Times Of Kerala With ) + With Bang Welcomes Kerala India A 2019 Videos Of Times Entertainment 0); console.log(ip)

The code (Math.floor(Math.random() * 255) + 1) means generate a random number between 1 and 255.

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