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I am trying to create fake IP address using the following javascript random method. But not works.

any one help me to get the correct way to do this?

here is my try: I am looking like ( "192.168.10.2")

 console.log( Math.Rfid Smart Is System Authentication Document 0b5000b A With B5000b random(256) + "." + Math.random(256)Archives Blog Bridge Bridge Blog Blog Liquors Liquors Archives q5TdXq + "."Is B5000b 0b5000b A Smart Authentication Document System Rfid With +Rfid With Authentication System Document B5000b A Is 0b5000b Smart MathAuthentication Is B5000b With Smart Rfid A 0b5000b System Document .random(256) + "."Authentication With A B5000b Rfid Smart Is System Document 0b5000b + Math.random(256) );

marked as duplicate by John3136, JJJ, T.J. Crowder Apr 18 '17 at 5:50

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7

The code should be :

var ip = Smart System B5000b Is Document Rfid Authentication With A 0b5000b (Math.floor(Math.random() * 255) + 1)+"."+(Math.floor(Math.random() *Is 0b5000b Authentication Smart A Document Rfid System B5000b With 255) + 0)+"."+(Math.floor(Math.random() *B5000b A Is Smart Authentication Document System Rfid With 0b5000b System A Is Smart B5000b 0b5000b Authentication Document Rfid With 255) + 0)+"."+(Math.floor(Math.random() * 255Is Authentication With 0b5000b A B5000b Rfid Document System Smart ) + 0b5000b Authentication Smart Is A B5000b With Rfid Document System 0); console.log(ip)

The code (Math.floor(Math.random() * 255) + 1) means generate a random number between 1 and 255.

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